In each instance, draw a diagram.

1. The index of refraction of air is 1.000. The index of refraction of water is 1.333. Find the angle of refraction for a ray of light that enters a bucket of water from air at an angle of 25.0° to the normal.

Rewrite Snell’s Law to solve for the refracted angle. The Snell’s Law formula can be found on p. 566 of Holt.

Since the light started in the air and entered the water, the light ray in the air is the incident ray, and the light ray in the water is the refracted ray.

25°

18°

2. A ray of light traveling in air enters a slab of transparent material. The incoming ray makes an angle of 40.0° with the normal. The reflected ray makes an angle of 26.0° with the normal. Find the index of refraction of the transparent material.

The incoming ray is the incident ray. Rewrite Snell’s Law to solve for the index of refraction of the transparent material.

40°

26°

3. The index of refraction of diamond is 2.419. Find the angle of refraction of a ray of light that enters a diamond from air at an angle of 15.0° to the normal.

Rewrite Snell’s Law to solve for angle of refraction.

15°

6°

4. A light ray of wavelength 589 nm travelling through the air strikes a smooth, flat slab of crown glass (n=1.52) at an angle of 30.0° to the normal. Find the angle of refraction, .

Rewrite Snell’s Law to solve for angle of refraction.

30°

19.2°